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start date: Fri, 13 Jul 2007 17:00:49 +0800,    posted on: microsoft.public.dotnet.framework.adonet        back       

Thread Index
  1    Angela Yan


Exception at SqlCommand.Connection.Open() in nested TransactionScope   
Hi,

I have a VB class to update a MS SQL server according to different incoming 
parameters in .Net 2.0. However, I keep getting the error message 
"Communication with the underlying transaction manager has failed." when I 
have nested TransactionScope. I am quite new to this topic, please kindly 
correct me if my implementation is incorrect.


Public Class UpdateAssignment

    MainFunction( param 1, param2)
        Try

            Using scope As TransactionScope = New TransactionScope()
                .....
                .....
                Function2(param2)

                scope.Complete()
            End Using
        Catch ex As System.Exception
            IsSuccess = False
        End Try
    End Function

    Function2
         Try
            Using scope As TransactionScope = New TransactionScope()

            For i = 0 To 10
                Function3
            Next

            scope.Complete()
            End Using

        Catch ex As System.Exception
            IsSuccess = False
        End Try
    End Function

    Function3
        Dim oSqlConnection As SqlConnection = New 
Data.SqlClient.SqlConnection
        Dim oSqlCommand As SqlCommand = New Data.SqlClient.SqlCommand

        Try
            Using scope As TransactionScope = New TransactionScope()

            oSqlConnection.ConnectionString = ConnectionString1
            oSqlCommand.Connection = oSqlConnection
            ...'Add param here
            ...
            oSqlCommand.Connection.Open()
            oSqlCommand.ExecuteNonQuery()

            scope.Complete()
            End Using

        Catch ex As System.Exception
            IsSuccess = False
        Finally
            oSqlCommand.Dispose()
            oSqlConnection.Dispose()
        End Try
    End Function
End


The exception will occur at the oSqlCommand.Connection.Open() in Function3 
when it loops for the second time. The error message is "Communication with 
the underlying transaction manager has failed." The inner exception is 
"Error HRESULT E_FAIL has been returned from a call to a COM component." 
Attached also the stack trace:


System.Transactions.TransactionManagerCommunicationException was caught
  Message="Communication with the underlying transaction manager has 
failed."
  Source="System.Transactions"
  StackTrace:
       at 
System.Transactions.TransactionInterop.GetOletxTransactionFromTransmitterPropigationToken(Byte[] 
propagationToken)
       at 
System.Transactions.TransactionStatePSPEOperation.PSPEPromote(InternalTransaction 
tx)
       at 
System.Transactions.TransactionStateDelegatedBase.EnterState(InternalTransaction 
tx)
       at System.Transactions.EnlistableStates.Promote(InternalTransaction 
tx)
       at System.Transactions.Transaction.Promote()
       at 
System.Transactions.TransactionInterop.ConvertToOletxTransaction(Transaction 
transaction)
       at System.Transactions.TransactionInterop.GetExportCookie(Transaction 
transaction, Byte[] whereabouts)
       at 
System.Data.SqlClient.SqlInternalConnection.EnlistNonNull(Transaction tx)
       at System.Data.SqlClient.SqlInternalConnection.Enlist(Transaction tx)
       at 
System.Data.SqlClient.SqlInternalConnectionTds.Activate(Transaction 
transaction)
       at 
System.Data.ProviderBase.DbConnectionInternal.ActivateConnection(Transaction 
transaction)
       at 
System.Data.ProviderBase.DbConnectionPool.GetConnection(DbConnection 
owningObject)
       at 
System.Data.ProviderBase.DbConnectionFactory.GetConnection(DbConnection 
owningConnection)
       at 
System.Data.ProviderBase.DbConnectionClosed.OpenConnection(DbConnection 
outerConnection, DbConnectionFactory connectionFactory)
       at System.Data.SqlClient.SqlConnection.Open()
       at UpdateAssignment.Function3(TAJobAction JobAction) in 
http://server//Project/App_Code/UpdateAssignment.vb:line 169

Any help is greatly appreciated.

Thank you.
Angela
Date:Fri, 13 Jul 2007 17:00:49 +0800   Author:  

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